9x^2-103x+248=0

Solution for 9x^2-103x+248=0 equation:

9x^2-103x+248=0

a = 9; b = -103; c = +248;
Δ = b2-4ac
Δ = -1032-4·9·248
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-103)-41}{2*9}=\frac{62}{18}
=3+4/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-103)+41}{2*9}=\frac{144}{18}
=8
$